By Jones D.W.
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After writing key 7, we replace it with key 4. This process repeats until step F, where our last key written was 8, and all keys are less than 8. At this point, we terminate the run, and start another. Step A B C D E F G H Input 5-3-4-8-6-7 5-3-4-8 5-3-4 5-3 5 Buffer 6-7 8-7 8-4 3-4 5-4 5 Output 6 7-6 8-7-6 3 | 8-7-6 4-3 | 8-7-6 5-4-3 | 8-7-6 Figure 4-2: Replacement Selection This strategy simply utilizes an intermediate buffer to hold values until the appropriate time for output. Using random numbers as input, the average length of a run is twice the length of the buffer.
A buffer is allocated in memory to act as a holding place for several records. Initially, the buffer is filled. Then, the following steps are repeated until the input is exhausted: • Select the record with the smallest key that is ≥ the key of the last record written. • If all keys are smaller than the key of the last record written, then we have reached the end of a run. Select the record with the smallest key as the first record of the next run. • Write the selected record. • Replace the selected record with a new record from input.
Step A B C D E F G H Input 5-3-4-8-6-7 5-3-4-8 5-3-4 5-3 5 Buffer 6-7 8-7 8-4 3-4 5-4 5 Output 6 7-6 8-7-6 3 | 8-7-6 4-3 | 8-7-6 5-4-3 | 8-7-6 Figure 4-2: Replacement Selection This strategy simply utilizes an intermediate buffer to hold values until the appropriate time for output. Using random numbers as input, the average length of a run is twice the length of the buffer. However, if the data is somewhat ordered, runs can be extremely long. Thus, this method is more effective than doing partial sorts.
Arithmetic tutorials by Jones D.W.